Collecting Numbers

Easy C++

Key Idea: Solution implementation

Solution

#include <bits/stdc++.h>
using namespace std;
//author: von_Braun
#define ll long long
#define lli long long int
#define pb push_back
#define rep(var, start, num) for(ulli var = start; var <start + num; var++)
#define all(x) x.begin(), x.end()
#define ulli unsigned long long int
#define ull unsigned long long
bool sortbysec(const pair<ll,ll> &a,const pair<ll,ll> &b) { return (a.second < b.second); }

void solve() {
    int n;
    cin>>n;
    int a[n];
    rep(i,0,n) {cin>>a[i];}
    sort(a,a+n);
    reverse(a,a+n);
    int ans=1;
    int cnt=1;
    int mine = INT_MAX;
    rep(i,0,n) {
        if (a[i] < mine) {
            mine = a[i];
            ans = max(ans,cnt);
            cnt=1;
        } else if (a[i] > mine) {
            
        }
    }
}
int main() {
    //add quotes incase input output file
    //freopen(input.txt,r,stdin);
    //freopen(output.txt,w,stdout);
    ios_base::sync_with_stdio(0);
    cin.tie(0); cout.tie(0);
    int tc = 1;
    //cin >> tc;
    for (int t = 1; t <= tc; t++) {
        solve();
    }
}