Counting Rooms
Hard C++
Key Idea: Solution implementation
Solution
#include <bits/stdc++.h>
using namespace std;
//author: von_Braun
#define ll long long
#define lli long long int
#define pb push_back
#define rep(var, start, num) for(ulli var = start; var <start + num; var++)
#define all(x) x.begin(), x.end()
#define ulli unsigned long long int
#define ull unsigned long long
bool sortbysec(const pair<ll,ll> &a,const pair<ll,ll> &b) { return (a.second < b.second); }
void dfs(int i, int j, vector<vector<char>> &a, vector<vector<bool>> &vis) {
int n = a.size();
int m = a[0].size();
vis[i][j]=1;
if (i-1 >= 0) {
if (a[i-1][j] == '.' && (vis[i-1][j]==0)) {dfs(i-1, j, a, vis);}
}
if (i+1 < n) {
if (a[i+1][j] == '.' && (vis[i+1][j]==0)) {dfs(i+1, j, a, vis);}
}
if (j-1 >= 0) {
if (a[i][j-1] == '.' && (vis[i][j-1]==0)) {dfs(i, j-1, a, vis);}
}
if (j+1 < m) {
if (a[i][j+1] == '.' && (vis[i][j+1]==0)) {dfs(i, j+1, a, vis);}
}
}
void solve() {
int cnt=0;
int n, m;
cin>>n>>m;
vector<vector<char>> a(n, vector<char>(m));
vector<vector<bool>> vis(n, vector<bool>(m, 0));
rep(i,0,n) {
rep(j,0,m) {
cin>>a[i][j];
}
}
rep(i,0,n) {
rep(j,0,m) {
if (a[i][j] == '.' && vis[i][j] == 0) {
cnt++;
dfs(i, j, a, vis);
}
}
}
cout<<cnt<<endl;
}
int main() {
//add quotes incase input output file
//freopen(input.txt,r,stdin);
//freopen(output.txt,w,stdout);
ios_base::sync_with_stdio(0);
cin.tie(0); cout.tie(0);
int tc = 1;
// cin >> tc;
for (int t = 1; t <= tc; t++) {
solve();
}
}