Edit Distance
Hard C++
Key Idea: Solution implementation
Solution
#include <bits/stdc++.h>
using namespace std;
//author: von_Braun
#define ll long long
#define lli long long int
#define pb push_back
#define rep(var, start, num) for(ulli var = start; var <start + num; var++)
#define all(x) x.begin(), x.end()
#define ulli unsigned long long int
#define ull unsigned long long
bool sortbysec(const pair<ll,ll> &a,const pair<ll,ll> &b) { return (a.second < b.second); }
int ans(int i, int j, string &s1, string &s2, vector<vector<int>> &dp) {
if (dp[i][j]!=-1) {return dp[i][j];}
if (i==0) {
if (j==0) {
return dp[i][j] = !(s1[i] == s2[j]);
} else {
bool fl=0;
for(int k =0;k<=j;k++) {
if (s1[i]==s2[k]) {fl=1; break;}
}
return dp[i][j] = !fl + j;
}
}
if (j == 0) {
//i!=0
bool fl=0;
for(int k =0;k<=i;k++) {
if (s1[k]==s2[j]) {fl=1; break;}
}
return dp[i][j] = !fl + i;
// return dp[i][j] = !(s1[i] == s2[j]) + ans(i-1,j,s1,s2,dp);
}
if (s1[i] == s2[j]) {
return dp[i][j] = ans(i-1,j-1,s1,s2,dp);
}
//if not same, I can remove, add, modify;
int remove_i = 1+ans(i-1,j,s1,s2,dp);
int remove_j = 1 + ans(i,j-1,s1,s2,dp);
int edit = 1 + ans(i-1,j-1,s1,s2,dp);
// int add_i = 1 + ans(i-1,j,s1,s2);
// int add_j = 1 + ans(i,j-1,s1,s2);
return dp[i][j] = min({remove_i, remove_j, edit});
}
void solve() {
string s1,s2;
cin>>s1>>s2;
int n = s1.size();
int m = s2.size();
vector<vector<int>> dp(n,vector<int>(m,-1));
cout<<ans(n-1,m-1,s1,s2,dp);
}
int main() {
//add quotes incase input output file
//freopen(input.txt,r,stdin);
//freopen(output.txt,w,stdout);
ios_base::sync_with_stdio(0);
cin.tie(0); cout.tie(0);
int tc = 1;
// cin >> tc;
for (int t = 1; t <= tc; t++) {
solve();
}
}