Ferris Wheel
Key Idea: Two-pointer greedy: try to pair the lightest remaining person with the heaviest, otherwise seat the heaviest alone.
Solution
#include <bits/stdc++.h>
using namespace std;
//author: von_Braun
#define ll long long
#define lli long long int
#define pb push_back
#define rep(var, start, num) for(ulli var = start; var <start + num; var++)
#define all(x) x.begin(), x.end()
#define ulli unsigned long long int
#define ull unsigned long long
bool sortbysec(const pair<ll,ll> &a,const pair<ll,ll> &b) { return (a.second < b.second); }
void solve() {
int n,x;
cin>>n>>x;
int ans=0;
int k;
multiset<int> S;
rep(i,0,n) {cin>>k; S.insert(k);}
while(S.size()>0) {
auto start = S.begin();
auto huh = S.upper_bound(x - *start);
if (huh!=S.begin()) {huh--;
if (huh!=S.begin()) {
S.erase(huh);
S.erase(S.begin());
ans++;} else {
ans++;
S.erase(huh);
} } else {
ans++;
S.erase(huh);
}
}
cout<<ans<<endl;
}
int main() {
//add quotes incase input output file
//freopen(input.txt,r,stdin);
//freopen(output.txt,w,stdout);
ios_base::sync_with_stdio(0);
cin.tie(0); cout.tie(0);
int tc = 1;
// cin >> tc;
for (int t = 1; t <= tc; t++) {
solve();
}
}