Minimizing Coins
Hard C++
Key Idea: Solution implementation
Solution
#include <bits/stdc++.h>
using namespace std;
//author: von_Braun
#define ll long long
#define lli long long int
#define pb push_back
#define rep(var, start, num) for(ulli var = start; var <start + num; var++)
#define all(x) x.begin(), x.end()
#define ulli unsigned long long int
#define ull unsigned long long
bool sortbysec(const pair<ll,ll> &a,const pair<ll,ll> &b) { return (a.second < b.second); }
bool possible(int n, vector<int> &pos, vector<int> &coins) {
if (n<coins[0]) {return 0;}
// cout<<"pos called "<<n<<endl;
if (n<0) {return 0;}
if (n==0) {return 1;}
if (pos[n]!=-1) {return pos[n];}
bool ret=0;
for(auto x:coins) {
if (n-x>=0) {ret = ret||possible(n-x,pos,coins);}
}
return pos[n] = ret;
}
int ncoins(int t, vector<int> &coins, vector<int> &dp, vector<int> &pos) {
int ans=INT_MAX;
if (t==0) {return 0;}
if (dp[t]!=-1) {return dp[t];}
for(auto x:coins) {
if (possible(t-x,pos,coins)) {
ans = min(ans,1+ncoins(t-x, coins, dp, pos));
pos[t]=1;
}
}
return dp[t]=ans;
}
void solve() {
int n, t;
cin>>n>>t;
vector<int> coins(n);
rep(i,0,n) {cin>>coins[i];}
sort(coins.begin(),coins.end());
vector<int> dp(t+1,-1);
vector<int> pos(t+1,-1);
if (possible(t,pos,coins)==0) {cout<<"-1\n";} else {
cout<<ncoins(t,coins, dp, pos);
}
}
int main() {
//add quotes incase input output file
//freopen(input.txt,r,stdin);
//freopen(output.txt,w,stdout);
ios_base::sync_with_stdio(0);
cin.tie(0); cout.tie(0);
int tc = 1;
//cin >> tc;
for (int t = 1; t <= tc; t++) {
solve();
}
}