Round Trip
Hard C++
Key Idea: Solution implementation
Solution
#include <bits/stdc++.h>
using namespace std;
//author: von_Braun
#define ll long long
#define lli long long int
#define pb push_back
#define rep(var, start, num) for(ulli var = start; var <start + num; var++)
#define all(x) x.begin(), x.end()
#define ulli unsigned long long int
#define ull unsigned long long
bool sortbysec(const pair<ll,ll> &a,const pair<ll,ll> &b) { return (a.second < b.second); }
int finalnode = -1;
bool dfs(int n, vector<vector<int>> &adj, vector<bool> &vis, int cnt, vector<int> &visc, vector<int> &parent) {
vis[n]=1;
bool z=0;
visc[n] = cnt;
for(auto x:adj[n]) {
if (vis[x]==1) {
if (cnt - visc[x] >=2) {
parent[x] = n;
finalnode = x;
return 1;
}
} else {
parent[x]=n;
z = z|dfs(x, adj, vis, cnt+1, visc, parent);
if (z==1) {return 1;}
}
}
return z;
}
void solve() {
int n,m;
cin>>n>>m;
vector<vector<int>> adj(n+1, vector<int>());
int a,b;
rep(i,0,m) {
cin>>a>>b;
adj[a].pb(b);
adj[b].pb(a);
}
vector<bool> vis(n+1, 0);
vector<int> parent(n+1, -1);
vector<int> visc(n+1, INT_MAX);
bool fl=0;
for(int i =0;i<n;i++) {
if (vis[i] == 0) {
fl = dfs(i, adj, vis, 0, visc, parent);
if (fl) {break;}
}
}
if (fl==0) {cout<<"IMPOSSIBLE\n";} else {
vector<int> ans;
int f = finalnode;
while(1) {
ans.push_back(f);
f = parent[f];
if (f==finalnode) {
ans.push_back(f);
break;
}
}
reverse(all(ans));
cout<<ans.size()<<endl;
for(auto x:ans) {cout<<x<<" ";}
cout<<endl;
}
}
int main() {
//add quotes incase input output file
//freopen(input.txt,r,stdin);
//freopen(output.txt,w,stdout);
ios_base::sync_with_stdio(0);
cin.tie(0); cout.tie(0);
int tc = 1;
// cin >> tc;
for (int t = 1; t <= tc; t++) {
solve();
}
}