Sum of Four Values
Key Idea: Fix the first two values, then two-pointer over the sorted remainder to complete the target sum.
Solution
#include <bits/stdc++.h>
using namespace std;
//author: von_Braun
#define ll long long
#define lli long long int
#define pb push_back
#define rep(var, start, num) for(ulli var = start; var <start + num; var++)
#define all(x) x.begin(), x.end()
#define ulli unsigned long long int
#define ull unsigned long long
bool sortbysec(const pair<ll,ll> &a,const pair<ll,ll> &b) { return (a.second < b.second); }
void solve() {
ll n,x;
cin>>n>>x;
// vector<ll> a(n);
vector<pair<ll,ll>> a(n);
map<ll,ll> mp;
bool fl=0;
map<ll,ll> pos;
rep(i,0,n) {cin>>a[i].first; a[i].second=i;}
sort(all(a));
auto twosum = [&](ll si, ll ts){
int l = si;
int r = n-1;
while(l<r) {
if (a[l].first + a[r].first < ts) {l++;}
else if (a[l].first + a[r].first > ts) {r--;}
else {cout<<a[l].second+1<<" "<<a[r].second+1<<" "; return 1;}
}
return 0;
};
rep(i,0,n) {
rep(j,i+1,n-1-i) {
if (x-a[i].first-a[j].first < a[j].first) {break;}
fl = twosum(j+1, x-a[i].first-a[j].first);
if (fl) {cout<<a[i].second+1<<" "<<a[j].second+1<<endl; break;}
}
if (fl) {break;}
}
if (!fl) {cout<<"IMPOSSIBLE\n";}
}
int main() {
//add quotes incase input output file
//freopen(input.txt,r,stdin);
//freopen(output.txt,w,stdout);
ios_base::sync_with_stdio(0);
cin.tie(0); cout.tie(0);
int tc = 1;
// cin >> tc;
for (int t = 1; t <= tc; t++) {
solve();
}
}