Problem 2 The Lazy Cow
USACO Silver
Key Idea
Solution implementation
Solution
#include <bits/stdc++.h>
using namespace std;
//author: von_Braun
#define ll long long
#define lli long long int
#define pb push_back
#define rep(var, start, num) for(ulli var = start; var <start + num; var++)
#define all(x) x.begin(), x.end()
#define ulli unsigned long long int
#define ull unsigned long long
bool sortbysec(const pair<ll,ll> &a,const pair<ll,ll> &b) { return (a.second < b.second); }
lli computeksum(int i, int j, int k, vector<vector<lli>> &rowpref) {
ll int n = rowpref.size();
//forward, from ith row
ll int ci=i;
lli sum=0;
// cout<<"n "<<n<<endl;
while(1) {
if (ci> i + k) {break;}
if (ci >= n) {break;}
ll int d = ci - i;
ll int lj = j-(k-d)+1;
ll int rj = j+(k-d)+1;
lj = max(lj, 1LL);
rj = min(rj, n);
sum += (rowpref[ci][rj] - rowpref[ci][lj-1]);
ci++;
}
//behind i
ci=i-1;
while(1) {
if (ci< i - k) {break;}
if (ci < 0) {break;}
ll int d = i - ci;
ll int lj = j-(k-d)+1;
ll int rj = j+(k-d)+1;
lj = max(lj, 1LL);
rj = min(rj, n);
sum += (rowpref[ci][rj] - rowpref[ci][lj-1]);
ci--;
}
return sum;
}
void solve() {
int n,k;
cin>>n>>k;
vector<vector<lli>> grid(n, vector<lli>(n, 0));
rep(i,0,n) {
rep(j,0,n) {
cin>>grid[i][j];
}
}
vector<vector<ll int>> rowpref(n, vector<lli>(n+1,0));
vector<vector<ll int>> colpref(n+1, vector<lli>(n,0));
//compute rowpref
rep(i,0,n) {
rep(j,1,n){
rowpref[i][j] = rowpref[i][j-1] + grid[i][j-1];
}
}
lli ans=INT64_MIN;
rep(i,0,n) {
rep(j,0,n) {
ans = max(ans, computeksum(i, j, k, rowpref));
}
}
cout<<ans<<endl;
}
int main() {
//add quotes incase input output file
freopen("lazy.in","r",stdin);
freopen("lazy.out","w",stdout);
ios_base::sync_with_stdio(0);
cin.tie(0); cout.tie(0);
int tc = 1;
// cin >> tc;
for (int t = 1; t <= tc; t++) {
solve();
}
}